Q1. Make correct statements by filling in the symbols ⊂ or ⊂ in the blank spaces:
(A set is a subset of another set if every element of the first set is also an element of the second.)
(i) {2,3,4}…{1,2,3,4,5}
Sol. Every element of the set {2,3,4} is also an element of the set {1,2,3,4,5}.
∴ {2,3,4}⊂{1,2,3,4,5}
(ii) {a,b,c}…{b,c,d}
Sol. a∈{a,b,c} but a∈/{b,c,d}.
∴ {a,b,c}⊂{b,c,d}
(iii) {x:x is a student of Class XI of your school}…{x:x student of your school}
Sol. Every student of Class XI of your school is a student of your school.
∴ {x:x is a student of Class XI of your school}⊂{x:x student of your school}
(iv) {x:x is a circle in the plane}…{x:x is a circle in the same plane with radius 1 unit}
Sol. A circle of radius 2 units in the plane is an element of the first set but not of the second.
∴ {x:x is a circle in the plane}⊂{x:x is a circle in the same plane with radius 1 unit}
(v) {x:x is a triangle in a plane}…{x:x is a rectangle in the plane}
Sol. A triangle is not a rectangle.
∴ {x:x is a triangle in a plane}⊂{x:x is a rectangle in the plane}
(vi) {x:x is an equilateral triangle in a plane}…{x:x is a triangle in the same plane}
Sol. Every equilateral triangle is a triangle.
∴ {x:x is an equilateral triangle in a plane}⊂{x:x is a triangle in the same plane}
(vii) {x:x is an even natural number}…{x:x is an integer}
Sol. Every even natural number is an integer.
∴ {x:x is an even natural number}⊂{x:x is an integer}
Q2. Examine whether the following statements are true or false:
(i) {a,b}⊂{b,c,a}
Sol. Both a and b are elements of {b,c,a}, so {a,b}⊂{b,c,a}.
∴ The statement is false.
(ii) {a,e}⊂{x:x is a vowel in the English alphabet}
Sol. The set of vowels in the English alphabet is {a,e,i,o,u}.
Every element of {a,e} is also an element of {a,e,i,o,u}, so {a,e}⊂{a,e,i,o,u}.
∴ The statement is true.
(iii) {1,2,3}⊂{1,3,5}
Sol. 2∈{1,2,3} but 2∈/{1,3,5}.
∴ The statement is false.
(iv) {a}⊂{a,b,c}
Sol. The only element a of {a} is an element of {a,b,c}.
∴ The statement is true.
(v) {a}∈{a,b,c}
Sol. The elements of {a,b,c} are a,b,c; the set {a} is not one of them (the correct statements are a∈{a,b,c} and {a}⊂{a,b,c}).
∴ The statement is false.
(vi) {x:x is an even natural number less than 6}⊂{x:x is a natural number which divides 36}
Sol. The even natural numbers less than 6 are 2,4, so the first set is {2,4}.
The natural numbers which divide 36 are 1,2,3,4,6,9,12,18,36, so the second set is {1,2,3,4,6,9,12,18,36}.
Both 2 and 4 are in the second set.
∴ The statement is true.
Q3. Let A={1,2,{3,4},5}. Which of the following statements are incorrect and why?
(The elements of A are 1, 2, {3,4} and 5. Note that 3 and 4 by themselves are not elements of A.)
(i) {3,4}⊂A
Sol. 3∈{3,4} but 3∈/A.
∴ {3,4}⊂A is incorrect.
(ii) {3,4}∈A
Sol. {3,4} is an element of A.
∴ {3,4}∈A is correct.
(iii) {{3,4}}⊂A
Sol. The only element of {{3,4}} is {3,4}, which is an element of A.
∴ {{3,4}}⊂A is correct.
(iv) 1∈A
Sol. 1 is an element of A.
∴ 1∈A is correct.
(v) 1⊂A
Sol. 1 is an element, not a set, so the symbol ⊂ cannot be used between 1 and A (the correct forms are 1∈A or {1}⊂A).
∴ 1⊂A is incorrect.
(vi) {1,2,5}⊂A
Sol. Each of 1,2,5 is an element of A.
∴ {1,2,5}⊂A is correct.
(vii) {1,2,5}∈A
Sol. {1,2,5} is not one of the four elements of A.
∴ {1,2,5}∈A is incorrect.
(viii) {1,2,3}⊂A
Sol. 3∈{1,2,3} but 3∈/A.
∴ {1,2,3}⊂A is incorrect.
(ix) ϕ∈A
Sol. ϕ is not one of the elements of A.
∴ ϕ∈A is incorrect.
(x) ϕ⊂A
Sol. ϕ is a subset of every set.
∴ ϕ⊂A is correct.
(xi) {ϕ}⊂A
Sol. The only element of {ϕ} is ϕ, and ϕ∈/A.
∴ {ϕ}⊂A is incorrect.
Hence, the incorrect statements are (i), (v), (vii), (viii), (ix) and (xi).
Q4. Write down all the subsets of the following sets
(i) {a}
(ii) {a,b}
(iii) {1,2,3}
(iv) ϕ
(i) The subsets of {a} are ∅ and {a}.
(ii) The subsets of {a,b} are ∅, {a}, {b} and {a,b}.
(iii) The subsets of {1,2,3} are ∅, {1}, {2}, {3}, {1,2}, {1,3}, {2,3} and {1,2,3}.
(iv) The only subset of ∅ is ∅.
Q5. Write the following as intervals:
(i) {x:x∈R, −4<x≤6}
(ii) {x:x∈R, −12<x<−10}
(iii) {x:x∈R, 0≤x<7}
(iv) {x:x∈R, 3≤x≤4}
(i) {x:x∈R,−4<x≤6}=(−4,6]
(ii) {x:x∈R,−12<x<−10}=(−12,−10)
(iii) {x:x∈R,0≤x<7}=[0,7)
(iv) {x:x∈R,3≤x≤4}=[3,4]
Q6. Write the following intervals in set-builder form:
(i) (−3,0)
(ii) [6,12]
(iii) (6,12]
(iv) [−23,5)
(i) (−3,0)={x:x∈R,−3<x<0}
(ii) [6,12]={x:x∈R,6≤x≤12}
(iii) (6,12]={x:x∈R,6<x≤12}
(iv) [−23,5)={x:x∈R,−23≤x<5}
Q7. What universal set(s) would you propose for each of the following:
(i) The set of right triangles.
Sol. For the set of right triangles, the universal set can be the set of all triangles or the set of all polygons.
(ii) The set of isosceles triangles.
Sol. For the set of isosceles triangles, the universal set can be the set of all triangles, the set of all polygons or the set of all two-dimensional figures.
Q8. Given the sets A={1,3,5}, B={2,4,6} and C={0,2,4,6,8}, which of the following may be considered as universal set (s) for all the three sets A, B and C
(i) {0,1,2,3,4,5,6}
(ii) ϕ
(iii) {0,1,2,3,4,5,6,7,8,9,10}
(iv) {1,2,3,4,5,6,7,8}
Sol. A universal set for A, B and C must contain every element of all three sets, i.e., it must contain A∪B∪C={0,1,2,3,4,5,6,8}.
(i) 8∈C but 8∈/{0,1,2,3,4,5,6}.
∴ It cannot be a universal set.
(ii) ϕ has no element, so A,B,C are not subsets of it.
∴ It cannot be a universal set.
(iii) {0,1,2,3,4,5,6,7,8,9,10} contains every element of A, B and C.
∴ It can be a universal set.
(iv) 0∈C but 0∈/{1,2,3,4,5,6,7,8}.
∴ It cannot be a universal set.
Hence, only the set in (iii) can be considered as the universal set.